INDIAN WELLS, Calif. (AP) — Daniil Medvedev handed top-seeded Carlos Alcaraz his first loss of the year and advanced to the final at Indian Wells with a 6-3, 7-6 (3) victory Saturday.
The 11th-seeded Medvedev, from Russia, will face second-seeded Jannik Sinner of Italy. Sinner beat Alexander Zverev 6-2, 6-4.
Alcaraz had won 16 straight matches this year, including titles at the Australian Open and Qatar Open. But Medvedev ended the possibility of an Alcaraz vs. Sinner final. Medvedev had dropped his last four meetings against Alcaraz, including a loss in the Indian Wells final in 2024. This was Medvedev’s first victory over him since the U.S. Open semifinals in 2023.
Sinner made quick work of Zverev, beating him in 1 hour, 23 minutes. Sinner notched six aces against the fourth-seeded Zverev.
Zverev won his first eight points on serve. But Sinner broke Zverev in both the fifth and seventh games to secure the first set. Sinner now leads the head-to-head series against Zverev 7-4.
Neither Medvedev nor Sinner has dropped a set yet in this tournament. Sinner has won his last three matches against Medvedev, including in the U.S. Open quarterfinals in 2024.
